Solve y-1=-3/4(x-2)

$$y - 1 = - \frac { 3 } { 4 } ( x - 2 )$$

Solve for x

$$x=\frac{10-4y}{3}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{3}{4} by x-2.

$$y-1=-\frac{3}{4}x+\frac{3}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{3}{4}x+\frac{3}{2}=y-1$$

Subtract \frac{3}{2} from both sides.

$$-\frac{3}{4}x=y-1-\frac{3}{2}$$

Subtract \frac{3}{2} from -1 to get -\frac{5}{2}.

$$-\frac{3}{4}x=y-\frac{5}{2}$$

Divide both sides of the equation by -\frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{4}x}{-\frac{3}{4}}=\frac{y-\frac{5}{2}}{-\frac{3}{4}}$$

Dividing by -\frac{3}{4} undoes the multiplication by -\frac{3}{4}.

$$x=\frac{y-\frac{5}{2}}{-\frac{3}{4}}$$

Divide y-\frac{5}{2} by -\frac{3}{4} by multiplying y-\frac{5}{2} by the reciprocal of -\frac{3}{4}.

$$x=\frac{10-4y}{3}$$

Solve for y

$$y=-\frac{3x}{4}+\frac{5}{2}$$

Solution Steps

Use the distributive property to multiply -\frac{3}{4} by x-2.

$$y-1=-\frac{3}{4}x+\frac{3}{2}$$

Add 1 to both sides.

$$y=-\frac{3}{4}x+\frac{3}{2}+1$$

Add \frac{3}{2} and 1 to get \frac{5}{2}.

$$y=-\frac{3}{4}x+\frac{5}{2}$$