Solve y-1=3/2(x-(-1))

$$y - 1 = \frac { 3 } { 2 } ( x - ( - 1 ) )$$

Solve for x

$$x=\frac{2y-5}{3}$$

Steps for Solving Linear Equation

The opposite of -1 is 1.

$$y-1=\frac{3}{2}\left(x+1\right)$$

Use the distributive property to multiply \frac{3}{2} by x+1.

$$y-1=\frac{3}{2}x+\frac{3}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{2}x+\frac{3}{2}=y-1$$

Subtract \frac{3}{2} from both sides.

$$\frac{3}{2}x=y-1-\frac{3}{2}$$

Subtract \frac{3}{2} from -1 to get -\frac{5}{2}.

$$\frac{3}{2}x=y-\frac{5}{2}$$

Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}x}{\frac{3}{2}}=\frac{y-\frac{5}{2}}{\frac{3}{2}}$$

Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.

$$x=\frac{y-\frac{5}{2}}{\frac{3}{2}}$$

Divide y-\frac{5}{2} by \frac{3}{2} by multiplying y-\frac{5}{2} by the reciprocal of \frac{3}{2}.

$$x=\frac{2y-5}{3}$$

Solve for y

$$y=\frac{3x+5}{2}$$

Solution Steps

The opposite of -1 is 1.

$$y-1=\frac{3}{2}\left(x+1\right)$$

Use the distributive property to multiply \frac{3}{2} by x+1.

$$y-1=\frac{3}{2}x+\frac{3}{2}$$

Add 1 to both sides.

$$y=\frac{3}{2}x+\frac{3}{2}+1$$

Add \frac{3}{2} and 1 to get \frac{5}{2}.

$$y=\frac{3}{2}x+\frac{5}{2}$$