Solve y-(-8)+2(-10)+8)

$$y - ( - 8 ) + 2 ( - 10 ) + 8 )$$

Evaluate

$$y-4$$

Solution Steps

The opposite of -8 is 8.

$$y+8+2\left(-10\right)+8$$

Multiply 2 and -10 to get -20.

$$y+8-20+8$$

Subtract 20 from 8 to get -12.

$$y-12+8$$

Add -12 and 8 to get -4.

$$y-4$$

Differentiate w.r.t. y

$$1$$

Steps Using Derivative Rule for Sum

The opposite of -8 is 8.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y+8+2\left(-10\right)+8)$$

Multiply 2 and -10 to get -20.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y+8-20+8)$$

Subtract 20 from 8 to get -12.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-12+8)$$

Add -12 and 8 to get -4.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y-4)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$