Solve y-2/x+1y=(x+1)^3

$$y - \frac { 2 } { x + 1 } y = ( x + 1 ) ^ { 3 }$$

Solve for y

$$y=\frac{\left(x+1\right)^{4}}{x-1}$$

$$|x|\neq 1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x+1.

$$\left(x+1\right)y-2y=\left(x+1\right)\left(x+1\right)^{3}$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$\left(x+1\right)y-2y=\left(x+1\right)^{4}$$

Use the distributive property to multiply x+1 by y.

$$xy+y-2y=\left(x+1\right)^{4}$$

Combine y and -2y to get -y.

$$xy-y=\left(x+1\right)^{4}$$

Combine all terms containing y.

$$\left(x-1\right)y=\left(x+1\right)^{4}$$

Divide both sides by x-1.

$$\frac{\left(x-1\right)y}{x-1}=\frac{\left(x+1\right)^{4}}{x-1}$$

Dividing by x-1 undoes the multiplication by x-1.

$$y=\frac{\left(x+1\right)^{4}}{x-1}$$