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Evaluate (complex solution)
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y\times \left(2i\right)\sqrt{5}\left(\sqrt{5}-\sqrt{-5}\right)
Factor -20=\left(2i\right)^{2}\times 5. Rewrite the square root of the product \sqrt{\left(2i\right)^{2}\times 5} as the product of square roots \sqrt{\left(2i\right)^{2}}\sqrt{5}. Take the square root of \left(2i\right)^{2}.
y\times \left(2i\right)\sqrt{5}\left(\sqrt{5}-\sqrt{5}i\right)
Factor -5=5\left(-1\right). Rewrite the square root of the product \sqrt{5\left(-1\right)} as the product of square roots \sqrt{5}\sqrt{-1}. By definition, the square root of -1 is i.
y\times \left(2i\right)\sqrt{5}\left(\sqrt{5}-i\sqrt{5}\right)
Multiply -1 and i to get -i.
y\times \left(2i\right)\sqrt{5}\left(1-i\right)\sqrt{5}
Combine \sqrt{5} and -i\sqrt{5} to get \left(1-i\right)\sqrt{5}.
y\left(2i\times 1+2\left(-1\right)i^{2}\right)\sqrt{5}\sqrt{5}
Multiply 2i times 1-i.
y\left(2i\times 1+2\left(-1\right)\left(-1\right)\right)\sqrt{5}\sqrt{5}
By definition, i^{2} is -1.
y\left(2+2i\right)\sqrt{5}\sqrt{5}
Do the multiplications. Reorder the terms.
y\left(2+2i\right)\times 5
Multiply \sqrt{5} and \sqrt{5} to get 5.
y\left(2\times 5+2i\times 5\right)
Multiply 2+2i times 5.
y\left(10+10i\right)
Do the multiplications.