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\left(y^{3}+4r^{2}\right)\left(y^{6}-4r^{2}y^{3}+16r^{4}\right)
Rewrite y^{9}+64r^{6} as \left(y^{3}\right)^{3}+\left(4r^{2}\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).