Solve y^4-9x=4

$$y ^ { 4 } - 9 x = 4$$

Solve for x

$$x=\frac{y^{4}-4}{9}$$

Steps for Solving Linear Equation

Subtract y^{4} from both sides.

$$-9x=4-y^{4}$$

Divide both sides by -9.

$$\frac{-9x}{-9}=\frac{4-y^{4}}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$x=\frac{4-y^{4}}{-9}$$

Divide -y^{4}+4 by -9.

$$x=\frac{y^{4}-4}{9}$$

Solve for y (complex solution)

$$y=i\sqrt[4]{9x+4}$$

$$y=\sqrt[4]{9x+4}$$

$$y=-\sqrt[4]{9x+4}$$

$$y=-i\sqrt[4]{9x+4}$$

Solve for y

$$y=\sqrt[4]{9x+4}$$

$$y=-\sqrt[4]{9x+4}\text{, }x\geq -\frac{4}{9}$$