Solve y^2-8x+2+9=0

$$y ^ { 2 } - 8 x + 2 + 9 = 0$$

Solve for x

$$x=\frac{y^{2}+11}{8}$$

Steps for Solving Linear Equation

Add 2 and 9 to get 11.

$$y^{2}-8x+11=0$$

Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-8x+11=-y^{2}$$

Subtract 11 from both sides.

$$-8x=-y^{2}-11$$

Divide both sides by -8.

$$\frac{-8x}{-8}=\frac{-y^{2}-11}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$x=\frac{-y^{2}-11}{-8}$$

Divide -y^{2}-11 by -8.

$$x=\frac{y^{2}+11}{8}$$

Solve for y (complex solution)

$$y=-\sqrt{8x-11}$$

$$y=\sqrt{8x-11}$$

Solve for y

$$y=\sqrt{8x-11}$$

$$y=-\sqrt{8x-11}\text{, }x\geq \frac{11}{8}$$