Solve y^2-4x-2y=3

$$y ^ { 2 } - 4 x - 2 y = 3$$

Solve for x

$$x=\frac{\left(y-3\right)\left(y+1\right)}{4}$$

Steps for Solving Linear Equation

Subtract y^{2} from both sides.

$$-4x-2y=3-y^{2}$$

Add 2y to both sides.

$$-4x=3-y^{2}+2y$$

The equation is in standard form.

$$-4x=3+2y-y^{2}$$

Divide both sides by -4.

$$\frac{-4x}{-4}=-\frac{\left(y-3\right)\left(y+1\right)}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=-\frac{\left(y-3\right)\left(y+1\right)}{-4}$$

Divide -\left(-3+y\right)\left(1+y\right) by -4.

$$x=\frac{\left(y-3\right)\left(y+1\right)}{4}$$

Solve for y (complex solution)

$$y=2\sqrt{x+1}+1$$

$$y=-2\sqrt{x+1}+1$$

Solve for y

$$y=2\sqrt{x+1}+1$$

$$y=-2\sqrt{x+1}+1\text{, }x\geq -1$$