Solve y^2-4x=6

$$y ^ { 2 } - 4 x = 6$$

Solve for x

$$x=\frac{y^{2}-6}{4}$$

Steps for Solving Linear Equation

Subtract y^{2} from both sides.

$$-4x=6-y^{2}$$

Divide both sides by -4.

$$\frac{-4x}{-4}=\frac{6-y^{2}}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=\frac{6-y^{2}}{-4}$$

Divide 6-y^{2} by -4.

$$x=\frac{y^{2}}{4}-\frac{3}{2}$$

Solve for y (complex solution)

$$y=-\sqrt{4x+6}$$

$$y=\sqrt{4x+6}$$

Solve for y

$$y=\sqrt{4x+6}$$

$$y=-\sqrt{4x+6}\text{, }x\geq -\frac{3}{2}$$