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y^{2}-2y-8+y=6
Add y to both sides.
y^{2}-y-8=6
Combine -2y and y to get -y.
y^{2}-y-8-6=0
Subtract 6 from both sides.
y^{2}-y-14=0
Subtract 6 from -8 to get -14.
y=\frac{-\left(-1\right)±\sqrt{1-4\left(-14\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and -14 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-\left(-1\right)±\sqrt{1+56}}{2}
Multiply -4 times -14.
y=\frac{-\left(-1\right)±\sqrt{57}}{2}
Add 1 to 56.
y=\frac{1±\sqrt{57}}{2}
The opposite of -1 is 1.
y=\frac{\sqrt{57}+1}{2}
Now solve the equation y=\frac{1±\sqrt{57}}{2} when ± is plus. Add 1 to \sqrt{57}.
y=\frac{1-\sqrt{57}}{2}
Now solve the equation y=\frac{1±\sqrt{57}}{2} when ± is minus. Subtract \sqrt{57} from 1.
y=\frac{\sqrt{57}+1}{2} y=\frac{1-\sqrt{57}}{2}
The equation is now solved.
y^{2}-2y-8+y=6
Add y to both sides.
y^{2}-y-8=6
Combine -2y and y to get -y.
y^{2}-y=6+8
Add 8 to both sides.
y^{2}-y=14
Add 6 and 8 to get 14.
y^{2}-y+\left(-\frac{1}{2}\right)^{2}=14+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}-y+\frac{1}{4}=14+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
y^{2}-y+\frac{1}{4}=\frac{57}{4}
Add 14 to \frac{1}{4}.
\left(y-\frac{1}{2}\right)^{2}=\frac{57}{4}
Factor y^{2}-y+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y-\frac{1}{2}\right)^{2}}=\sqrt{\frac{57}{4}}
Take the square root of both sides of the equation.
y-\frac{1}{2}=\frac{\sqrt{57}}{2} y-\frac{1}{2}=-\frac{\sqrt{57}}{2}
Simplify.
y=\frac{\sqrt{57}+1}{2} y=\frac{1-\sqrt{57}}{2}
Add \frac{1}{2} to both sides of the equation.