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y^{2}-41=0
Subtract 29 from -12 to get -41.
y^{2}=41
Add 41 to both sides. Anything plus zero gives itself.
y=\sqrt{41} y=-\sqrt{41}
Take the square root of both sides of the equation.
y^{2}-41=0
Subtract 29 from -12 to get -41.
y=\frac{0±\sqrt{0^{2}-4\left(-41\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -41 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{0±\sqrt{-4\left(-41\right)}}{2}
Square 0.
y=\frac{0±\sqrt{164}}{2}
Multiply -4 times -41.
y=\frac{0±2\sqrt{41}}{2}
Take the square root of 164.
y=\sqrt{41}
Now solve the equation y=\frac{0±2\sqrt{41}}{2} when ± is plus.
y=-\sqrt{41}
Now solve the equation y=\frac{0±2\sqrt{41}}{2} when ± is minus.
y=\sqrt{41} y=-\sqrt{41}
The equation is now solved.