Solve y^2div7=5

$$y ^ { 2 } \div 7 = 5$$

Solve for y

$$y=\sqrt{35}\approx 5.916079783$$

$$y=-\sqrt{35}\approx -5.916079783$$

Steps by Finding Square Root

Multiply both sides by 7.

$$y^{2}=5\times 7$$

Multiply 5 and 7 to get 35.

$$y^{2}=35$$

Take the square root of both sides of the equation.

$$y=\sqrt{35} y=-\sqrt{35}$$

Steps Using the Quadratic Formula

Multiply both sides by 7.

$$y^{2}=5\times 7$$

Multiply 5 and 7 to get 35.

$$y^{2}=35$$

Subtract 35 from both sides.

$$y^{2}-35=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -35 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-35\right)}}{2}$$

Square 0.

$$y=\frac{0±\sqrt{-4\left(-35\right)}}{2}$$

Multiply -4 times -35.

$$y=\frac{0±\sqrt{140}}{2}$$

Take the square root of 140.

$$y=\frac{0±2\sqrt{35}}{2}$$

Now solve the equation y=\frac{0±2\sqrt{35}}{2} when ± is plus.

$$y=\sqrt{35}$$

Now solve the equation y=\frac{0±2\sqrt{35}}{2} when ± is minus.

$$y=-\sqrt{35}$$

The equation is now solved.

$$y=\sqrt{35} y=-\sqrt{35}$$