Solve y^2=12+4

$$y ^ { 2 } = 12 + 4$$

Solve for y

$$y=4$$

$$y=-4$$

Steps Using Difference of Squares

Add 12 and 4 to get 16.

$$y^{2}=16$$

Subtract 16 from both sides.

$$y^{2}-16=0$$

Consider y^{2}-16. Rewrite y^{2}-16 as y^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(y-4\right)\left(y+4\right)=0$$

To find equation solutions, solve y-4=0 and y+4=0.

$$y=4 y=-4$$

Steps by Finding Square Root

Add 12 and 4 to get 16.

$$y^{2}=16$$

Take the square root of both sides of the equation.

$$y=4 y=-4$$

Steps Using the Quadratic Formula

Add 12 and 4 to get 16.

$$y^{2}=16$$

Subtract 16 from both sides.

$$y^{2}-16=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -16 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-16\right)}}{2}$$

Square 0.

$$y=\frac{0±\sqrt{-4\left(-16\right)}}{2}$$

Multiply -4 times -16.

$$y=\frac{0±\sqrt{64}}{2}$$

Take the square root of 64.

$$y=\frac{0±8}{2}$$

Now solve the equation y=\frac{0±8}{2} when ± is plus. Divide 8 by 2.

$$y=4$$

Now solve the equation y=\frac{0±8}{2} when ± is minus. Divide -8 by 2.

$$y=-4$$

The equation is now solved.

$$y=4 y=-4$$