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\left(-3+y-2x\right)\left(-3+y+2x\right)
Rewrite y^{2}+9-6y-4x^{2} as \left(-3+y\right)^{2}-\left(2x\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-2x+y-3\right)\left(2x+y-3\right)
Reorder the terms.