Solve for x
x=-\frac{y^{2}}{8}-1
Solve for y (complex solution)
y=-2\sqrt{-2x-2}
y=2\sqrt{-2x-2}
Solve for y
y=2\sqrt{-2x-2}
y=-2\sqrt{-2x-2}\text{, }x\leq -1
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8x+8=-y^{2}
Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.
8x=-y^{2}-8
Subtract 8 from both sides.
\frac{8x}{8}=\frac{-y^{2}-8}{8}
Divide both sides by 8.
x=\frac{-y^{2}-8}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{y^{2}}{8}-1
Divide -y^{2}-8 by 8.
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