Solve y^2+3x-17=35x

$$y ^ { 2 } + 3 x - 17 = 35 x$$

Solve for x

$$x=\frac{y^{2}-17}{32}$$

Steps for Solving Linear Equation

Subtract 35x from both sides.

$$y^{2}+3x-17-35x=0$$

Combine 3x and -35x to get -32x.

$$y^{2}-32x-17=0$$

Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-32x-17=-y^{2}$$

Add 17 to both sides.

$$-32x=-y^{2}+17$$

The equation is in standard form.

$$-32x=17-y^{2}$$

Divide both sides by -32.

$$\frac{-32x}{-32}=\frac{17-y^{2}}{-32}$$

Dividing by -32 undoes the multiplication by -32.

$$x=\frac{17-y^{2}}{-32}$$

Divide -y^{2}+17 by -32.

$$x=\frac{y^{2}-17}{32}$$

Solve for y (complex solution)

$$y=-\sqrt{32x+17}$$

$$y=\sqrt{32x+17}$$

Solve for y

$$y=\sqrt{32x+17}$$

$$y=-\sqrt{32x+17}\text{, }x\geq -\frac{17}{32}$$