Solve y^-1=x+2

$$y ^ { - 1 } = x + 2$$

Solve for y

$$y=\frac{1}{x+2}$$

$$x\neq -2$$

Steps for Solving Linear Equation

Reorder the terms.

$$\frac{1}{y}=x+2$$

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.

$$1=yx+y\times 2$$

Swap sides so that all variable terms are on the left hand side.

$$yx+y\times 2=1$$

Combine all terms containing y.

$$\left(x+2\right)y=1$$

Divide both sides by x+2.

$$\frac{\left(x+2\right)y}{x+2}=\frac{1}{x+2}$$

Dividing by x+2 undoes the multiplication by x+2.

$$y=\frac{1}{x+2}$$

Variable y cannot be equal to 0.

$$y=\frac{1}{x+2}\text{, }y\neq 0$$

Solve for x

$$x=-2+\frac{1}{y}$$

$$y\neq 0$$