Solve y^prime=operatorname{Ir}(x^2-3x+7)

$$y ^ { \prime } = \operatorname { Ir } ( x ^ { 2 } - 3 x + 7 )$$

Solve for I

$$\left\{\begin{matrix}\\I=0\text{, }&\text{unconditionally}\\I\in \mathrm{R}\text{, }&r=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply Ir by x^{2}-3x+7.

$$\frac{\mathrm{d}}{\mathrm{d}x}(y)=Irx^{2}-3Irx+7Ir$$

Swap sides so that all variable terms are on the left hand side.

$$Irx^{2}-3Irx+7Ir=\frac{\mathrm{d}}{\mathrm{d}x}(y)$$

Combine all terms containing I.

$$\left(rx^{2}-3rx+7r\right)I=\frac{\mathrm{d}}{\mathrm{d}x}(y)$$

The equation is in standard form.

$$\left(rx^{2}-3rx+7r\right)I=0$$

Divide 0 by rx^{2}-3rx+7r.

$$I=0$$

Solve for r

$$\left\{\begin{matrix}\\r=0\text{, }&\text{unconditionally}\\r\in \mathrm{R}\text{, }&I=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply Ir by x^{2}-3x+7.

$$\frac{\mathrm{d}}{\mathrm{d}x}(y)=Irx^{2}-3Irx+7Ir$$

Swap sides so that all variable terms are on the left hand side.

$$Irx^{2}-3Irx+7Ir=\frac{\mathrm{d}}{\mathrm{d}x}(y)$$

Combine all terms containing r.

$$\left(Ix^{2}-3Ix+7I\right)r=\frac{\mathrm{d}}{\mathrm{d}x}(y)$$

The equation is in standard form.

$$\left(Ix^{2}-3Ix+7I\right)r=0$$

Divide 0 by Ix^{2}-3Ix+7I.

$$r=0$$