Solve for x
x=ye^{2y-5}
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xe^{5-2y}=y
Swap sides so that all variable terms are on the left hand side.
e^{5-2y}x=y
The equation is in standard form.
\frac{e^{5-2y}x}{e^{5-2y}}=\frac{y}{e^{5-2y}}
Divide both sides by e^{5-2y}.
x=\frac{y}{e^{5-2y}}
Dividing by e^{5-2y} undoes the multiplication by e^{5-2y}.
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