Solve for y
y=\frac{\left(x+1\right)\left(x-2\right)^{2}}{1-2x}
x\neq \frac{1}{2}
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y-2xy=x^{3}-3x^{2}+4
Subtract 2xy from both sides.
\left(1-2x\right)y=x^{3}-3x^{2}+4
Combine all terms containing y.
\frac{\left(1-2x\right)y}{1-2x}=\frac{\left(x+1\right)\left(x-2\right)^{2}}{1-2x}
Divide both sides by 1-2x.
y=\frac{\left(x+1\right)\left(x-2\right)^{2}}{1-2x}
Dividing by 1-2x undoes the multiplication by 1-2x.
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