Solve y=x^2

$$y = x ^ { 2 }$$

Solve for x

$$x=\sqrt{y}$$

$$x=-\sqrt{y}\text{, }y\geq 0$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=y$$

Take the square root of both sides of the equation.

$$x=\sqrt{y} x=-\sqrt{y}$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=y$$

Subtract y from both sides.

$$x^{2}-y=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -y for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-y\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-y\right)}}{2}$$

Multiply -4 times -y.

$$x=\frac{0±\sqrt{4y}}{2}$$

Take the square root of 4y.

$$x=\frac{0±2\sqrt{y}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{y}}{2} when ± is plus.

$$x=\sqrt{y}$$

Now solve the equation x=\frac{0±2\sqrt{y}}{2} when ± is minus.

$$x=-\sqrt{y}$$

The equation is now solved.

$$x=\sqrt{y} x=-\sqrt{y}$$

Solve for y

$$y=x^{2}$$