Solve for x (complex solution)
\left\{\begin{matrix}x=-\frac{1-y-my}{m\left(m+1\right)}\text{, }&m\neq -1\text{ and }m\neq 0\\x\in \mathrm{C}\text{, }&m=0\text{ and }y=1\end{matrix}\right.
Solve for x
\left\{\begin{matrix}x=-\frac{1-y-my}{m\left(m+1\right)}\text{, }&m\neq -1\text{ and }m\neq 0\\x\in \mathrm{R}\text{, }&m=0\text{ and }y=1\end{matrix}\right.
Solve for m (complex solution)
\left\{\begin{matrix}m=-\frac{\sqrt{x^{2}+2xy-4x+y^{2}}+x-y}{2x}\text{; }m=-\frac{-\sqrt{x^{2}+2xy-4x+y^{2}}+x-y}{2x}\text{, }&x\neq 0\\m=\frac{1-y}{y}\text{, }&x=0\text{ and }y\neq 0\end{matrix}\right.
Solve for m
\left\{\begin{matrix}m=-\frac{\sqrt{x^{2}+2xy-4x+y^{2}}+x-y}{2x}\text{; }m=-\frac{-\sqrt{x^{2}+2xy-4x+y^{2}}+x-y}{2x}\text{, }&x\neq 0\text{ and }\left(y\geq -x+2\sqrt{x}\text{ or }y\leq -x-2\sqrt{x}\text{ or }x<0\right)\\m=\frac{1-y}{y}\text{, }&x=0\text{ and }y\neq 0\end{matrix}\right.
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y\left(m+1\right)=mx\left(m+1\right)+1
Multiply both sides of the equation by m+1.
ym+y=mx\left(m+1\right)+1
Use the distributive property to multiply y by m+1.
ym+y=xm^{2}+mx+1
Use the distributive property to multiply mx by m+1.
xm^{2}+mx+1=ym+y
Swap sides so that all variable terms are on the left hand side.
xm^{2}+mx=ym+y-1
Subtract 1 from both sides.
\left(m^{2}+m\right)x=ym+y-1
Combine all terms containing x.
\left(m^{2}+m\right)x=my+y-1
The equation is in standard form.
\frac{\left(m^{2}+m\right)x}{m^{2}+m}=\frac{my+y-1}{m^{2}+m}
Divide both sides by m^{2}+m.
x=\frac{my+y-1}{m^{2}+m}
Dividing by m^{2}+m undoes the multiplication by m^{2}+m.
x=\frac{my+y-1}{m\left(m+1\right)}
Divide ym+y-1 by m^{2}+m.
y\left(m+1\right)=mx\left(m+1\right)+1
Multiply both sides of the equation by m+1.
ym+y=mx\left(m+1\right)+1
Use the distributive property to multiply y by m+1.
ym+y=xm^{2}+mx+1
Use the distributive property to multiply mx by m+1.
xm^{2}+mx+1=ym+y
Swap sides so that all variable terms are on the left hand side.
xm^{2}+mx=ym+y-1
Subtract 1 from both sides.
\left(m^{2}+m\right)x=ym+y-1
Combine all terms containing x.
\left(m^{2}+m\right)x=my+y-1
The equation is in standard form.
\frac{\left(m^{2}+m\right)x}{m^{2}+m}=\frac{my+y-1}{m^{2}+m}
Divide both sides by m^{2}+m.
x=\frac{my+y-1}{m^{2}+m}
Dividing by m^{2}+m undoes the multiplication by m^{2}+m.
x=\frac{my+y-1}{m\left(m+1\right)}
Divide ym+y-1 by m^{2}+m.
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