Solve y=kx-5

$$y = k x - 5$$

Solve for k (complex solution)

$$\left\{\begin{matrix}k=\frac{y+5}{x}\text{, }&x\neq 0\\k\in \mathrm{C}\text{, }&y=-5\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$kx-5=y$$

Add 5 to both sides.

$$kx=y+5$$

The equation is in standard form.

$$xk=y+5$$

Divide both sides by x.

$$\frac{xk}{x}=\frac{y+5}{x}$$

Dividing by x undoes the multiplication by x.

$$k=\frac{y+5}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=\frac{y+5}{k}\text{, }&k\neq 0\\x\in \mathrm{C}\text{, }&y=-5\text{ and }k=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$kx-5=y$$

Add 5 to both sides.

$$kx=y+5$$

Divide both sides by k.

$$\frac{kx}{k}=\frac{y+5}{k}$$

Dividing by k undoes the multiplication by k.

$$x=\frac{y+5}{k}$$

Solve for k

$$\left\{\begin{matrix}k=\frac{y+5}{x}\text{, }&x\neq 0\\k\in \mathrm{R}\text{, }&y=-5\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$kx-5=y$$

Add 5 to both sides.

$$kx=y+5$$

The equation is in standard form.

$$xk=y+5$$

Divide both sides by x.

$$\frac{xk}{x}=\frac{y+5}{x}$$

Dividing by x undoes the multiplication by x.

$$k=\frac{y+5}{x}$$

Solve for x

$$\left\{\begin{matrix}x=\frac{y+5}{k}\text{, }&k\neq 0\\x\in \mathrm{R}\text{, }&y=-5\text{ and }k=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$kx-5=y$$

Add 5 to both sides.

$$kx=y+5$$

Divide both sides by k.

$$\frac{kx}{k}=\frac{y+5}{k}$$

Dividing by k undoes the multiplication by k.

$$x=\frac{y+5}{k}$$