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e^{x}+x^{3}en\frac{\mathrm{d}}{\mathrm{d}x}(y)=y
Swap sides so that all variable terms are on the left hand side.
x^{3}en\frac{\mathrm{d}}{\mathrm{d}x}(y)=y-e^{x}
Subtract e^{x} from both sides.
0=y-e^{x}
The equation is in standard form.
n\in
This is false for any n.