Solve for B (complex solution)
\left\{\begin{matrix}B=\frac{y}{DT}\text{, }&T\neq 0\text{ and }D\neq 0\\B\in \mathrm{C}\text{, }&\left(T=0\text{ or }D=0\right)\text{ and }y=0\end{matrix}\right.
Solve for D (complex solution)
\left\{\begin{matrix}D=\frac{y}{BT}\text{, }&T\neq 0\text{ and }B\neq 0\\D\in \mathrm{C}\text{, }&\left(T=0\text{ or }B=0\right)\text{ and }y=0\end{matrix}\right.
Solve for B
\left\{\begin{matrix}B=\frac{y}{DT}\text{, }&T\neq 0\text{ and }D\neq 0\\B\in \mathrm{R}\text{, }&\left(T=0\text{ or }D=0\right)\text{ and }y=0\end{matrix}\right.
Solve for D
\left\{\begin{matrix}D=\frac{y}{BT}\text{, }&T\neq 0\text{ and }B\neq 0\\D\in \mathrm{R}\text{, }&\left(T=0\text{ or }B=0\right)\text{ and }y=0\end{matrix}\right.
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BDT=y
Swap sides so that all variable terms are on the left hand side.
DTB=y
The equation is in standard form.
\frac{DTB}{DT}=\frac{y}{DT}
Divide both sides by DT.
B=\frac{y}{DT}
Dividing by DT undoes the multiplication by DT.
BDT=y
Swap sides so that all variable terms are on the left hand side.
BTD=y
The equation is in standard form.
\frac{BTD}{BT}=\frac{y}{BT}
Divide both sides by BT.
D=\frac{y}{BT}
Dividing by BT undoes the multiplication by BT.
BDT=y
Swap sides so that all variable terms are on the left hand side.
DTB=y
The equation is in standard form.
\frac{DTB}{DT}=\frac{y}{DT}
Divide both sides by DT.
B=\frac{y}{DT}
Dividing by DT undoes the multiplication by DT.
BDT=y
Swap sides so that all variable terms are on the left hand side.
BTD=y
The equation is in standard form.
\frac{BTD}{BT}=\frac{y}{BT}
Divide both sides by BT.
D=\frac{y}{BT}
Dividing by BT undoes the multiplication by BT.
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