Solve for y
y=8\left(3x-2\right)^{3}
Solve for x
x=\frac{\sqrt[3]{y}+4}{6}
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y=8\left(27x^{3}-54x^{2}+36x-8\right)
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(3x-2\right)^{3}.
y=216x^{3}-432x^{2}+288x-64
Use the distributive property to multiply 8 by 27x^{3}-54x^{2}+36x-8.
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