Solve y=6sqrt{4+x}

$$y = 6 \sqrt { 4 + x }$$

Solve for x

$$x=\frac{y^{2}-144}{36}$$

$$y\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$6\sqrt{4+x}=y$$

Divide both sides by 6.

$$\frac{6\sqrt{x+4}}{6}=\frac{y}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$\sqrt{x+4}=\frac{y}{6}$$

Square both sides of the equation.

$$x+4=\frac{y^{2}}{36}$$

Subtract 4 from both sides of the equation.

$$x+4-4=\frac{y^{2}}{36}-4$$

Subtracting 4 from itself leaves 0.

$$x=\frac{y^{2}}{36}-4$$

Solve for x (complex solution)

$$x=\frac{y^{2}-144}{36}$$

$$arg(y)<\pi \text{ or }y=0$$

Solve for y (complex solution)

$$y=6\sqrt{x+4}$$

Solve for y

$$y=6\sqrt{x+4}$$

$$x\geq -4$$