Solve y=4+2/1-x

$$y = 4 + \frac { 2 } { 1 - x }$$

Solve for x

$$x=-\frac{6-y}{y-4}$$

$$y\neq 4$$

Steps for Solving Linear Equation

Variable x cannot be equal to 1 since division by zero is not defined. Multiply both sides of the equation by -x+1.

$$y\left(-x+1\right)=\left(-x+1\right)\times 4+2$$

Use the distributive property to multiply y by -x+1.

$$-yx+y=\left(-x+1\right)\times 4+2$$

Use the distributive property to multiply -x+1 by 4.

$$-yx+y=-4x+4+2$$

Add 4 and 2 to get 6.

$$-yx+y=-4x+6$$

Add 4x to both sides.

$$-yx+y+4x=6$$

Subtract y from both sides.

$$-yx+4x=6-y$$

Combine all terms containing x.

$$\left(-y+4\right)x=6-y$$

The equation is in standard form.

$$\left(4-y\right)x=6-y$$

Divide both sides by -y+4.

$$\frac{\left(4-y\right)x}{4-y}=\frac{6-y}{4-y}$$

Dividing by -y+4 undoes the multiplication by -y+4.

$$x=\frac{6-y}{4-y}$$

Variable x cannot be equal to 1.

$$x=\frac{6-y}{4-y}\text{, }x\neq 1$$

Solve for y

$$y=-\frac{2\left(2x-3\right)}{1-x}$$

$$x\neq 1$$