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3xy+x=y
Swap sides so that all variable terms are on the left hand side.
\left(3y+1\right)x=y
Combine all terms containing x.
\frac{\left(3y+1\right)x}{3y+1}=\frac{y}{3y+1}
Divide both sides by 3y+1.
x=\frac{y}{3y+1}
Dividing by 3y+1 undoes the multiplication by 3y+1.
y-3xy=x
Subtract 3xy from both sides.
\left(1-3x\right)y=x
Combine all terms containing y.
\frac{\left(1-3x\right)y}{1-3x}=\frac{x}{1-3x}
Divide both sides by 1-3x.
y=\frac{x}{1-3x}
Dividing by 1-3x undoes the multiplication by 1-3x.