Solve y=3x+(a^2-4)

$$y = 3 x + ( a ^ { 2 } - 4 )$$

Solve for x

$$x=\frac{y-a^{2}+4}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$3x+a^{2}-4=y$$

Subtract a^{2} from both sides.

$$3x-4=y-a^{2}$$

Add 4 to both sides.

$$3x=y-a^{2}+4$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{y-a^{2}+4}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{y-a^{2}+4}{3}$$

Solve for a (complex solution)

$$a=-\sqrt{4+y-3x}$$

$$a=\sqrt{4+y-3x}$$

Solve for a

$$a=\sqrt{4+y-3x}$$

$$a=-\sqrt{4+y-3x}\text{, }y\geq -\left(4-3x\right)$$