Solve y=3-sqrt{x+1}

$$y = 3 - \sqrt { x + 1 }$$

Solve for x

$$x=\left(y-4\right)\left(y-2\right)$$

$$3-y\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$3-\sqrt{x+1}=y$$

Subtract 3 from both sides.

$$-\sqrt{x+1}=y-3$$

Divide both sides by -1.

$$\frac{-\sqrt{x+1}}{-1}=\frac{y-3}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$\sqrt{x+1}=\frac{y-3}{-1}$$

Divide y-3 by -1.

$$\sqrt{x+1}=3-y$$

Square both sides of the equation.

$$x+1=\left(3-y\right)^{2}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\left(3-y\right)^{2}-1$$

Subtracting 1 from itself leaves 0.

$$x=\left(3-y\right)^{2}-1$$

Subtract 1 from \left(-y+3\right)^{2}.

$$x=y^{2}-6y+8$$

Solve for x (complex solution)

$$x=\left(y-4\right)\left(y-2\right)$$

$$y=3\text{ or }arg(3-y)<\pi$$

Solve for y (complex solution)

$$y=-\sqrt{x+1}+3$$

Solve for y

$$y=-\sqrt{x+1}+3$$

$$x\geq -1$$