Solve for y
y=3\left(\left(x-9\right)^{3}-4\right)
Solve for x
x=\frac{3^{\frac{2}{3}}\sqrt[3]{y+12}+27}{3}
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y=3\left(x^{3}-27x^{2}+243x-729\right)-12
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-9\right)^{3}.
y=3x^{3}-81x^{2}+729x-2187-12
Use the distributive property to multiply 3 by x^{3}-27x^{2}+243x-729.
y=3x^{3}-81x^{2}+729x-2199
Subtract 12 from -2187 to get -2199.
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