Solve for y
y=2x^{3}+3\left(x+4\right)^{2}-7
Solve for x
x=\frac{\sqrt[3]{2\sqrt{y^{2}-59y+1714}+2y-59}+\sqrt[3]{-2\sqrt{y^{2}-59y+1714}+2y-59}-1}{2}
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y=3\left(x^{2}+8x+16\right)+2x^{3}-7
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+4\right)^{2}.
y=3x^{2}+24x+48+2x^{3}-7
Use the distributive property to multiply 3 by x^{2}+8x+16.
y=3x^{2}+24x+41+2x^{3}
Subtract 7 from 48 to get 41.
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