Solve y=3(-2)^3+2(-2)^2+6

$$y = 3 ( - 2 ) ^ { 3 } + 2 ( - 2 ) ^ { 2 } + 6$$

Solve for y

$$y=-10$$

Steps for Solving Linear Equation

Calculate -2 to the power of 3 and get -8.

$$y=3\left(-8\right)+2\left(-2\right)^{2}+6$$

Multiply 3 and -8 to get -24.

$$y=-24+2\left(-2\right)^{2}+6$$

Calculate -2 to the power of 2 and get 4.

$$y=-24+2\times 4+6$$

Multiply 2 and 4 to get 8.

$$y=-24+8+6$$

Add -24 and 8 to get -16.

$$y=-16+6$$

Add -16 and 6 to get -10.

$$y=-10$$

Assign y

$$y≔-10$$