Solve for x
x=\left(2-y\right)^{2}-7
2-y\geq 0
Solve for x (complex solution)
x=\left(2-y\right)^{2}-7
y=2\text{ or }arg(2-y)<\pi
Solve for y (complex solution)
y=-\sqrt{x+7}+2
Solve for y
y=-\sqrt{x+7}+2
x\geq -7
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2-\sqrt{x+7}=y
Swap sides so that all variable terms are on the left hand side.
-\sqrt{x+7}=y-2
Subtract 2 from both sides.
\frac{-\sqrt{x+7}}{-1}=\frac{y-2}{-1}
Divide both sides by -1.
\sqrt{x+7}=\frac{y-2}{-1}
Dividing by -1 undoes the multiplication by -1.
\sqrt{x+7}=2-y
Divide y-2 by -1.
x+7=\left(2-y\right)^{2}
Square both sides of the equation.
x+7-7=\left(2-y\right)^{2}-7
Subtract 7 from both sides of the equation.
x=\left(2-y\right)^{2}-7
Subtracting 7 from itself leaves 0.
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Limits
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