Solve for y
y=2\left(x-5\right)\left(x^{2}-4x+7\right)
Solve for x
x=\frac{2^{\frac{2}{3}}\sqrt[3]{y+16}+6}{2}
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y=2\left(x^{3}-9x^{2}+27x-27\right)-16
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-3\right)^{3}.
y=2x^{3}-18x^{2}+54x-54-16
Use the distributive property to multiply 2 by x^{3}-9x^{2}+27x-27.
y=2x^{3}-18x^{2}+54x-70
Subtract 16 from -54 to get -70.
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