Solve for y
y=2\left(3x+1\right)^{3}
Solve for x
x=\frac{2^{\frac{2}{3}}\sqrt[3]{y}-2}{6}
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y=2\left(27x^{3}+27x^{2}+9x+1\right)
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(3x+1\right)^{3}.
y=54x^{3}+54x^{2}+18x+2
Use the distributive property to multiply 2 by 27x^{3}+27x^{2}+9x+1.
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