Solve y=2sqrt{2}x-2sqrt{2}-2

$$y = 2 \sqrt { 2 } x - 2 \sqrt { 2 } - 2$$

Solve for x

$$x=\frac{\sqrt{2}\left(y+2\right)+4}{4}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$2\sqrt{2}x-2\sqrt{2}-2=y$$

Add 2\sqrt{2} to both sides.

$$2\sqrt{2}x-2=y+2\sqrt{2}$$

Add 2 to both sides.

$$2\sqrt{2}x=y+2\sqrt{2}+2$$

Divide both sides by 2\sqrt{2}.

$$\frac{2\sqrt{2}x}{2\sqrt{2}}=\frac{y+2\sqrt{2}+2}{2\sqrt{2}}$$

Dividing by 2\sqrt{2} undoes the multiplication by 2\sqrt{2}.

$$x=\frac{y+2\sqrt{2}+2}{2\sqrt{2}}$$

Divide y+2\sqrt{2}+2 by 2\sqrt{2}.

$$x=\frac{\sqrt{2}y}{4}+\frac{\sqrt{2}}{2}+1$$

Solve for y

$$y=2\sqrt{2}x-2\sqrt{2}-2$$