Solve for y
y = \frac{19802}{11} = 1800\frac{2}{11} \approx 1800.181818182
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y≔\frac{19802}{11}
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y=\frac{19800}{11}+\frac{2}{11}
Convert 1800 to fraction \frac{19800}{11}.
y=\frac{19800+2}{11}
Since \frac{19800}{11} and \frac{2}{11} have the same denominator, add them by adding their numerators.
y=\frac{19802}{11}
Add 19800 and 2 to get 19802.
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