Solve y=-9sqrt{2x}

$$y = - 9 \sqrt { 2 x }$$

Solve for x

$$x=\frac{y^{2}}{162}$$

$$y\leq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$-9\sqrt{2x}=y$$

Divide both sides by -9.

$$\frac{-9\sqrt{2x}}{-9}=\frac{y}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$\sqrt{2x}=\frac{y}{-9}$$

Divide y by -9.

$$\sqrt{2x}=-\frac{y}{9}$$

Square both sides of the equation.

$$2x=\frac{y^{2}}{81}$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{y^{2}}{2\times 81}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{y^{2}}{2\times 81}$$

Divide \frac{y^{2}}{81} by 2.

$$x=\frac{y^{2}}{162}$$

Solve for x (complex solution)

$$x=\frac{y^{2}}{162}$$

$$arg(y)\geq \pi \text{ or }y=0$$

Solve for y

$$y=-9\sqrt{2x}$$

$$x\geq 0$$