Solve y=-8(x+1)^2+6

$$y = - 8 ( x + 1 ) ^ { 2 } + 6$$

Solve for y

$$y=-8\left(x+1\right)^{2}+6$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.

$$y=-8\left(x^{2}+2x+1\right)+6$$

Use the distributive property to multiply -8 by x^{2}+2x+1.

$$y=-8x^{2}-16x-8+6$$

Add -8 and 6 to get -2.

$$y=-8x^{2}-16x-2$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{12-2y}}{4}-1$$

$$x=\frac{\sqrt{12-2y}}{4}-1$$

Solve for x

$$x=-\frac{\sqrt{12-2y}}{4}-1$$

$$x=\frac{\sqrt{12-2y}}{4}-1\text{, }y\leq 6$$