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y=-5\left(-\frac{1}{8}x^{3}-\frac{9}{4}x^{2}-\frac{27}{2}x-27\right)+1
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(-\frac{1}{2}x-3\right)^{3}.
y=\frac{5}{8}x^{3}+\frac{45}{4}x^{2}+\frac{135}{2}x+135+1
Use the distributive property to multiply -5 by -\frac{1}{8}x^{3}-\frac{9}{4}x^{2}-\frac{27}{2}x-27.
y=\frac{5}{8}x^{3}+\frac{45}{4}x^{2}+\frac{135}{2}x+136
Add 135 and 1 to get 136.