Solve for y
y=-\left(\left(x-5\right)^{2}+25\right)
Solve for x (complex solution)
x=-i\sqrt{y+25}+5
x=i\sqrt{y+25}+5
Solve for x
x=-\sqrt{-y-25}+5
x=\sqrt{-y-25}+5\text{, }y\leq -25
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y=-25-\left(x^{2}-10x+25\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-5\right)^{2}.
y=-25-x^{2}+10x-25
To find the opposite of x^{2}-10x+25, find the opposite of each term.
y=-50-x^{2}+10x
Subtract 25 from -25 to get -50.
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