Solve for x
x=\frac{y^{2}}{25}
y\leq 0
Solve for x (complex solution)
x=\frac{y^{2}}{25}
arg(y)\geq \pi \text{ or }y=0
Solve for y (complex solution)
y=-5\sqrt{x}
Solve for y
y=-5\sqrt{x}
x\geq 0
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-2.5\sqrt{4x}=y
Swap sides so that all variable terms are on the left hand side.
\frac{-2.5\sqrt{4x}}{-2.5}=\frac{y}{-2.5}
Divide both sides of the equation by -2.5, which is the same as multiplying both sides by the reciprocal of the fraction.
\sqrt{4x}=\frac{y}{-2.5}
Dividing by -2.5 undoes the multiplication by -2.5.
\sqrt{4x}=-\frac{2y}{5}
Divide y by -2.5 by multiplying y by the reciprocal of -2.5.
4x=\frac{4y^{2}}{25}
Square both sides of the equation.
\frac{4x}{4}=\frac{4y^{2}}{4\times 25}
Divide both sides by 4.
x=\frac{4y^{2}}{4\times 25}
Dividing by 4 undoes the multiplication by 4.
x=\frac{y^{2}}{25}
Divide \frac{4y^{2}}{25} by 4.
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