Solve for y
y=\frac{1}{3}\approx 0.333333333
Assign y
y≔\frac{1}{3}
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y=-\frac{6+2}{3}+3
Multiply 2 and 3 to get 6.
y=-\frac{8}{3}+3
Add 6 and 2 to get 8.
y=-\frac{8}{3}+\frac{9}{3}
Convert 3 to fraction \frac{9}{3}.
y=\frac{-8+9}{3}
Since -\frac{8}{3} and \frac{9}{3} have the same denominator, add them by adding their numerators.
y=\frac{1}{3}
Add -8 and 9 to get 1.
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