Solve y=-16^{-1}x^{4}-4^-1*21x^3-8^-1*397x^2+4462x+87575

$$y = - 16 ^ { - 1 } x ^ { 4 } - 4 ^ { - 1 } \cdot 21 x ^ { 3 } - 8 ^ { - 1 } \cdot 397 x ^ { 2 } + 4462 x + 87575$$

Solve for y

$$y=-\frac{x^{4}}{16}-\frac{21x^{3}}{4}-\frac{397x^{2}}{8}+4462x+87575$$

Solution Steps

Calculate 16 to the power of -1 and get \frac{1}{16}.

$$y=-\frac{1}{16}x^{4}-4^{-1}\times 21x^{3}-8^{-1}\times 397x^{2}+4462x+87575$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$y=-\frac{1}{16}x^{4}-\frac{1}{4}\times 21x^{3}-8^{-1}\times 397x^{2}+4462x+87575$$

Multiply \frac{1}{4} and 21 to get \frac{21}{4}.

$$y=-\frac{1}{16}x^{4}-\frac{21}{4}x^{3}-8^{-1}\times 397x^{2}+4462x+87575$$

Calculate 8 to the power of -1 and get \frac{1}{8}.

$$y=-\frac{1}{16}x^{4}-\frac{21}{4}x^{3}-\frac{1}{8}\times 397x^{2}+4462x+87575$$

Multiply \frac{1}{8} and 397 to get \frac{397}{8}.

$$y=-\frac{1}{16}x^{4}-\frac{21}{4}x^{3}-\frac{397}{8}x^{2}+4462x+87575$$