Solve for y
y=-x\left(x^{2}-6x+12\right)
Solve for x
x=-\sqrt[3]{y+8}+2
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y=-\left(x^{3}-6x^{2}+12x-8\right)-8
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-2\right)^{3}.
y=-x^{3}+6x^{2}-12x+8-8
To find the opposite of x^{3}-6x^{2}+12x-8, find the opposite of each term.
y=-x^{3}+6x^{2}-12x
Subtract 8 from 8 to get 0.
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