Solve for y
y=-\left(\left(x+5\right)^{2}+8\right)
Solve for x (complex solution)
x=-i\sqrt{y+8}-5
x=i\sqrt{y+8}-5
Solve for x
x=-\left(\sqrt{-y-8}+5\right)
x=\sqrt{-y-8}-5\text{, }y\leq -8
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y=-\left(x^{2}+10x+25\right)-8
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+5\right)^{2}.
y=-x^{2}-10x-25-8
To find the opposite of x^{2}+10x+25, find the opposite of each term.
y=-x^{2}-10x-33
Subtract 8 from -25 to get -33.
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