Solve for y
y=-\left(x+1\right)^{2}+2
Solve for x (complex solution)
x=-\left(\sqrt{2-y}+1\right)
x=\sqrt{2-y}-1
Solve for x
x=-\left(\sqrt{2-y}+1\right)
x=\sqrt{2-y}-1\text{, }y\leq 2
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y=-\left(x^{2}+2x+1\right)+2
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.
y=-x^{2}-2x-1+2
To find the opposite of x^{2}+2x+1, find the opposite of each term.
y=-x^{2}-2x+1
Add -1 and 2 to get 1.
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